Skip to main content

Endpoint estimates for vector-valued multilinear commutator of fractional area integral operator

Abstract

In this paper, we prove the endpoint estimates for vector-valued multilinear commutator of fractional area integral operator.

MSC:42B20, 42B25.

1 Introduction

Let bBMO( R n ) and T be the Calderón-Zygmund operator, the commutator [b,T] generated by b and T is defined by

[b,T](f)(x)=b(x)T(f)(x)T(bf)(x).

A classical result of Coifman, Rochberb and Weiss (see [1]) proved that the commutator [b,T] is bounded on L p ( R n ) (1<p<). In [24], the boundedness properties of the commutators for the extreme values of p are obtained. In this paper, we introduce vector-valued multilinear commutator of fractional area integral operator and prove the endpoint estimates for the commutator | S ψ , δ b | r generated by the fractional area integral operator S ψ , δ and BMO functions.

2 Notations and results

We give the following definitions (see [2, 3, 57]).

Definition 1 Let 0<δ<n, a function ψ satisfies:

  1. (1)

    R n ψ(x)dx=0;

  2. (2)

    |ψ(x)|C ( 1 + | x | ) ( n + 1 δ ) ;

  3. (3)

    |ψ(x+y)ψ(x)|C | y | ε ( 1 + | x | ) ( n + 2 δ ) , 2|y|<|x|.

Suppose that 1<r<, b j (j=1,,m) are the fixed locally integrable functions on R n . Set Γ(x)={(y,t) R + n + 1 :|xy|t} and the eigenfunction by χ Γ ( x ) . We define the vector-valued multilinear commutator of fractional area integral operator by

| S ψ , δ b (f)(x) | r = ( i = 1 ( S ψ , δ b ( f i ) ( x ) ) r ) 1 / r ,

where

S ψ , δ b (f)(x)= ( Γ ( x ) | F t b ( f ) ( x , y ) | 2 d y d t t n + 1 ) 1 / 2

and

F t b ˜ (f)(x)= R n [ j = 1 m ( b j ( x ) b j ( z ) ) ] ψ t (yz)f(z)dz.

Definition 2 We call a locally integrable function b in the central BMO space, namely CMO( R n ), if the function b satisfies

b CMO = sup r > 1 |Q(0,r) | 1 Q |b(y) b Q |dy<.

We have

b CMO sup r > 1 inf c C |Q(0,r) | 1 Q |b(y)c|dy.

Definition 3 Let 0<δ<n, 1<p<n/δ. We call a locally integrable function b in B p δ ( R n ), if the function b satisfies

b B p δ = sup r > 1 r n ( 1 / p δ / n ) b χ Q ( 0 , r ) L p <.

Now we state our theorems as follows.

Theorem 1 Suppose 1<r<, 0<δ<n, and b =( b 1 ,, b m ) for b j BMO, 1jm. Then | S ψ , δ b | r is bounded from L n / δ to BMO( R n ).

Theorem 2 Let 1<r<, 0<δ<n, 1<p<n/δ, and b =( b 1 ,, b m ), with b j BMO( R n ), for 1jm. Then | S ψ , δ b | r is bounded from B p δ ( R n ) to CMO( R n ).

3 Proofs of theorems

We begin with a preliminaries lemma.

Lemma 1 (see [3, 4])

Let 1<r<, 0<δ<n, 1<p<n/δ, 1/q=1/pδ/n. Then | S ψ , δ | r is bounded from L p ( R n ) to L q ( R n ).

Proof of Theorem 1 It is only to prove that there exists a constant C Q , the following inequality holds:

1 | Q | Q || S ψ , δ b (f)(x) | r C Q |dxC | f | r L n / δ .

Fix a cube Q=Q( x 0 ,r), let f=g+h={ g i }+{ h i } for g i = f i χ Q , h i = f i χ ( Q ) c .

When m=1, set ( b 1 ) Q = | Q | 1 Q b 1 (y)dy, then

F t b 1 ( f i )(x,y)= ( b 1 ( x ) ( b 1 ) Q ) F t ( f i )(y) F t ( ( b 1 ( b 1 ) Q ) g i ) (y) F t ( ( b 1 ( b 1 ) Q ) h i ) (y),

so

| S ψ , δ b 1 ( f ) ( x ) | r | S ψ , δ ( ( ( b 1 ) 2 Q b 1 ) h ) ( x 0 ) r | ( i = 1 χ Γ ( x ) ( b 1 ( x ) ( b 1 ) Q ) F t ( f i ) ( y ) r ) 1 / r + ( i = 1 χ Γ ( x ) F t ( ( ( b 1 ) Q b 1 ) g i ) ( y ) r ) 1 / r + χ Γ ( x ) F t ( ( b 1 ( b 1 ) Q ) f 2 ) ( y ) χ Γ ( x 0 ) F t ( ( b 1 ( b 1 ) Q ) h ) ( y ) r = A ( x ) + B ( x ) + C ( x ) .

For A(x), suppose 1<p<n/δ, 1/q=1/pδ/n and 1/q+1/ q =1, by the Hölder inequality, then

1 | Q | Q | A ( x ) | d x = 1 | Q | Q | b 1 ( x ) ( b 1 ) Q | | S ψ , δ ( f ) ( x ) | r d x ( 1 | Q | Q | b 1 ( x ) ( b 1 ) Q | q d x ) 1 / q × ( 1 | Q | R n | S ψ , δ ( f ) ( x ) | r q χ Q ( x ) d x ) 1 / q C b 1 BMO | Q | 1 / q ( R n | f ( x ) | r p χ Q ( x ) d x ) 1 / p C b 1 BMO | Q | 1 / q × [ ( R n | f ( x ) | r n / δ d x ) δ p / n ( Q χ Q ( x ) d x ) 1 δ p / n ] 1 / p C b 1 BMO | Q | 1 / q | f | r L n / δ | Q | ( 1 δ p / n ) / p C b 1 BMO | f | r L n / δ .

For B(x), fix 1<u<n/δ, 1/v=1/uδ/n, by the Hölder inequality, then

1 | Q | Q | B ( x ) | d x = 1 | Q | Q | S ψ , δ ( ( b 1 ( b 1 ) Q ) g ) ( x ) | r d x ( 1 | Q | R n | S ψ , δ ( ( b 1 ( b 1 ) Q ) g ) ( x ) ) v d x | r ) 1 / v C | Q | 1 / v ( R n | b 1 ( x ) ( b 1 ) Q | u | f ( x ) | r u χ Q ( x ) d x ) 1 / u C ( 1 | Q | Q | b 1 ( x ) ( b 1 ) Q | u d x ) 1 / u | f | r L n / δ C b 1 BMO | f | r L n / δ .

For C(x), we have

C ( x ) = χ Γ ( x ) F t ( ( b 1 ( b 1 ) Q ) f 2 ) ( y ) χ Γ ( x 0 ) F t ( ( b 1 ( b 1 ) Q ) h ) ( y ) r [ R + n + 1 ( Q c | χ Γ ( x ) χ Γ ( x 0 ) b 1 ( z ) ( b 1 ) Q ψ t ( y z ) | | f ( z ) | r d z ) 2 d y d t t n + 1 ] 1 / 2 C Q c | b 1 ( z ) ( b 1 ) Q | | f ( z ) | r × | | x y | t t 1 n d y d t ( t + | y z | ) 2 n + 2 2 δ | x 0 y | t t 1 n d y d t ( t + | y z | ) 2 n + 2 2 δ | 1 / 2 d z C Q c | b 1 ( z ) ( b 1 ) Q | | f ( z ) | r × ( | y | t , | x + y z | t | 1 ( t + | x + y z | ) 2 n + 2 2 δ 1 ( t + | x 0 + y z | ) 2 n + 2 2 δ | d y d t t n 1 ) 1 / 2 d z Q c | b 1 ( z ) ( b 1 ) Q | | f ( z ) | r ( | y | t , | x + y z | t | x x 0 | t 1 n ( t + | x + y z | ) 2 n + 3 2 δ d y d t ) 1 / 2 d z .

Notice that when |y|t, 2t+|x+yz|2t+|xz||y|t+|xz|, and

0 t d t ( t + | x z | ) 2 n + 3 2 δ =C|xz | 2 n 1 + 2 δ ,

then, for xQ,

C ( x ) Q c | b 1 ( z ) ( b 1 ) Q | | f ( z ) | r ( | y | t 2 2 n + 3 2 δ | x 0 x | t 1 n d y d t ( 2 t + 2 | x + y z | ) 2 n + 3 2 δ ) 1 / 2 d z C Q c | b 1 ( z ) ( b 1 ) Q | | f ( z ) | r | x x 0 | 1 / 2 ( | y | t t 1 n d y d t ( t + | x z | ) 2 n + 3 2 δ ) 1 / 2 d z C Q c | b 1 ( z ) ( b 1 ) Q | | f ( z ) | r | x x 0 | 1 / 2 ( 0 t d t ( t + | x z | ) 2 n + 3 2 δ ) 1 / 2 d z C Q c | b 1 ( z ) ( b 1 ) Q | | f ( z ) | r | x 0 x | 1 / 2 | x 0 z | n + 1 / 2 δ d z C k = 1 2 k + 1 Q 2 k Q | b 1 ( z ) ( b 1 ) Q | | f ( z ) | r | x 0 x | 1 / 2 | x 0 z | n + 1 / 2 δ d z C k = 1 2 k / 2 | 2 k + 1 Q | 1 + δ / n 2 k + 1 Q | b 1 ( z ) ( b 1 ) Q | | f ( z ) | r d z C b 1 BMO k = 1 k 2 k / 2 | f | r L n / δ C b 1 BMO | f | r L n / δ ,

so that

1 | Q | Q |C(x)|dxC b 1 BMO | f | r L n / δ .

When m>1, let b Q =( ( b 1 ) Q ,, ( b m ) Q ) R n , where

( b j ) Q =|Q | 1 Q b j (y)dy,1jm,

let f=g+h={ g i }+{ h i } for g i = f i χ Q , h i = f i χ ( Q ) c . We have

F t b ( f i ) ( x , y ) = R n [ j = 1 m ( b 1 ( x ) b 1 ( z ) ) ] ψ t ( y z ) f i ( z ) d z = ( b 1 ( x ) ( b 1 ) Q ) ( b m ( x ) ( b m ) Q ) F t ( f i ) ( y ) + ( 1 ) m F t ( ( b 1 ( b 1 ) Q ) ( b m ( b m ) Q ) f i ) ( y ) + j = 1 m 1 σ C j m ( 1 ) m j ( b ( x ) b Q ) σ × R n ( b ( z ) b Q ) σ c ψ t ( y z ) f i ( z ) d z = ( b 1 ( x ) ( b 1 ) Q ) ( b m ( x ) ( b m ) Q ) F t ( f i ) ( y ) + ( 1 ) m F t ( ( b 1 ( b 1 ) Q ) ( b m ( b m ) Q ) g i ) ( y ) + ( 1 ) m F t ( ( b 1 ( b 1 ) Q ) ( b m ( b m ) Q ) h i ) ( y ) + j = 1 m 1 σ C j m ( 1 ) m j ( b ( x ) b Q ) σ F t ( ( b b Q ) σ c f i ) ( x , y ) ,

by the Minkowski inequality, we have

| | S ψ , δ b ( f ) ( x ) | r | S ψ , δ ( ( ( b 1 ) Q b 1 ) ( ( b m ) Q b m ) h ) ( x 0 ) | r | χ Γ ( x ) ( b 1 ( x ) ( b 1 ) Q ) ( b m ( x ) ( b m ) Q ) F t ( f ) ( y ) r + j = 1 m 1 σ C j m χ Γ ( x ) ( b ( x ) b Q ) σ F t ( ( b b Q ) σ c f ) ( x , y ) r + χ Γ ( x ) F t ( ( b 1 ( b 1 ) Q ) ( b m ( b m ) Q ) g ) ( y ) r + χ Γ ( x ) F t ( j = 1 m ( b j ( b j ) Q ) h ) ( y ) χ Γ ( x 0 ) F t ( j = 1 m ( b j ( b j ) Q ) h ) ( y ) r = M 1 ( x ) + M 2 ( x ) + M 3 ( x ) + M 4 ( x ) .

For M 1 (x), similar to the proof of m=1, we take 1<p<n/δ, 1/q=1/pδ/n, by the Hölder inequality and Lemma 1, we have

1 | Q | Q M 1 ( x ) d x ( 1 | Q | Q | j = 1 m ( b j ( x ) ( b j ) Q ) | q d x ) 1 / q ( 1 | Q | Q | S ψ , δ ( f ) ( x ) | r q d x ) 1 / q C b BMO | Q | 1 / q ( Q | f ( x ) | r p d x ) 1 / p C b BMO | Q | 1 / q ( Q | f ( x ) | r n / δ d x ) δ / n | Q | ( 1 ( δ p / n ) ) / p C b BMO | f | r L n / δ .

For M 2 (x), taking 1<p<n/δ, 1/q=1/pδ/n, we get

1 | Q | Q M 2 ( x ) d x C j = 1 m 1 σ C j m b σ BMO | Q | 1 / q ( R n | ( b ( x ) b Q ) σ c f ( x ) | r p χ Q ( x ) d x ) 1 / p C j = 1 m 1 σ C j m b σ BMO ( 1 | Q | Q | ( b ( x ) b Q ) σ c | q d x ) 1 / q | f | r L n / δ C j = 1 m 1 σ C j m b σ BMO b σ c BMO f L n / δ C b BMO | f | r L n / δ .

For M 3 (x), taking 1<p<n/δ, 1/q=1/pδ/n, we obtain

1 | Q | Q M 3 ( x ) d x ( 1 | Q | Q | S ψ , δ ( ( b 1 ( b 1 ) Q ) ( b m ( b m ) Q ) g ) ( x ) | r q d x ) 1 / q C | Q | 1 / q ( b 1 ( x ) ( b 1 ) Q ) ( b m ( x ) ( b m ) Q ) | g ( x ) | r L p C ( 1 | Q | Q | ( b 1 ( x ) ( b 1 ) Q ) ( b m ( x ) ( b m ) Q ) | q d x ) 1 / q | f | r L n / δ C b BMO | f | r L n / δ .

For M 4 (x), we have

M 4 ( x ) C Q c | x 0 x | 1 / 2 | x 0 z | ( n + 1 / 2 δ ) | j = 1 m ( b j ( z ) ( b j ) Q ) | | f ( z ) | r d z C k = 1 2 k Q 2 k 1 Q | x 0 x | 1 / 2 | x 0 z | ( n + 1 / 2 δ ) | j = 1 m ( b j ( z ) ( b j ) Q ) | | f ( z ) | r d z C k = 1 2 k Q 2 k 1 Q | x 0 x | 1 / 2 | x 0 z | n + 1 / 2 δ | j = 1 m ( b j ( z ) ( b j ) Q ) | | f ( z ) | r d z C k = 1 2 k / 2 1 | 2 k Q | 1 δ / n 2 k Q | j = 1 m ( b j ( z ) ( b j ) Q ) | | f ( z ) | r d z C k = 1 2 k / 2 ( 2 k Q | f ( z ) | r n / δ d z ) δ / n × ( 1 | 2 k Q | 2 k Q | j = 1 m ( b j ( z ) ( b j ) Q ) | n / ( n δ ) d z ) ( n δ ) / n C k = 1 k m 2 k / 2 j = 1 m b j BMO | f | r L n / δ C b BMO | f | r L n / δ ,

so

1 | Q | Q | M 4 (x)|dxC b BMO | f | r L n / δ .

This completes the proof of Theorem 1. □

Proof of Theorem 2 It is only to prove that there exists a constant C Q , for any of the cubes Q=Q(0,d) (d>1), the following inequality holds:

1 | Q | Q || S ψ , δ b (f)(x) | r C Q |dxC f B p δ .

Fix a cube Q=Q(0,d) (d>1). Let f=g+h={ g i }+{ h i }, where g i = f i χ Q , h i = f i χ ( Q ) c and b Q =( ( b 1 ) Q ,, ( b m ) Q ). For ( b j ) Q =|Q | 1 Q | b j (y)|dy, 1jm, we have

F t b ( f i ) ( x , y ) = R n [ j = 1 m ( b 1 ( x ) b 1 ( z ) ) ] ψ t ( y z ) f i ( z ) d z = ( b 1 ( x ) ( b 1 ) Q ) ( b m ( x ) ( b m ) Q ) F t ( f i ) ( y ) + ( 1 ) m F t ( ( b 1 ( b 1 ) Q ) ( b m ( b m ) Q ) g i ) ( y ) + ( 1 ) m F t ( ( b 1 ( b 1 ) Q ) ( b m ( b m ) Q ) h i ) ( y ) + j = 1 m 1 σ C j m ( 1 ) m j ( b ( x ) b Q ) σ F t ( ( b b Q ) σ c f i ) ( x , y ) .

By the Minkowski inequality, we have

| | S ψ , δ b ( f ) ( x ) | r | S ψ , δ ( ( ( b 1 ) Q b 1 ) ( ( b m ) Q b m ) h ) ( x 0 ) | r | χ Γ ( x ) ( b 1 ( x ) ( b 1 ) Q ) ( b m ( x ) ( b m ) Q ) F t ( f ) ( y ) r + j = 1 m 1 σ C j m χ Γ ( x ) ( b ( x ) b Q ) σ F t ( ( b b Q ) σ c f ) ( x , y ) r + χ Γ ( x ) F t ( ( b 1 ( b 1 ) Q ) ( b m ( b m ) Q ) g ) ( y ) r + χ Γ ( x ) F t ( j = 1 m ( b j ( b j ) Q ) h ) ( y ) χ Γ ( x 0 ) F t ( j = 1 m ( b j ( b j ) Q ) h ) ( y ) r = H 1 ( x ) + H 2 ( x ) + H 3 ( x ) + H 4 ( x ) .

For H 1 (x), take 1/q=1/pδ/n, by the Hölder inequality and Lemma 1, we have

1 | Q | Q H 1 ( x ) d x ( 1 | Q | Q | j = 1 m ( b j ( x ) ( b j ) Q ) | q d x ) 1 / q ( 1 | Q | Q | S ψ , δ ( f ) ( x ) | r q d x ) 1 / q C b BMO | Q | 1 / q ( R n | f ( x ) | r p χ Q ( x ) d x ) 1 / p C b BMO d n ( 1 / p δ / n ) | f | r χ Q L p C b BMO | f | r B p δ .

For H 2 (x), taking 1<u<p<n/δ, 1/v=1/uδ/n, we get

1 | Q | Q H 2 ( x ) d x C j = 1 m 1 σ C j m ( 1 | Q | Q | ( b ( x ) b Q ) σ | v d x ) 1 / v × ( 1 | Q | Q | S ψ , δ ( ( b b Q ) σ c f ) ( x ) | r u d x ) 1 / u C j = 1 m 1 σ C j m b σ BMO | Q | 1 / v ( R n | ( b ( x ) b Q ) σ c f ( x ) | r u χ Q ( x ) d x ) 1 / u C j = 1 m 1 σ C j m b σ BMO | Q | ( δ / n 1 / p ) | f | r χ Q L p × ( 1 | Q | Q | ( b ( x ) b Q ) σ c | p r / ( p r ) d x ) ( p u ) / p u C j = 1 m 1 σ C j m b σ BMO b σ c BMO d n ( 1 / p δ / n ) | f | r χ Q L p C b BMO | f | r B p δ .

For H 3 (x), taking 1<u<p<n/δ, 1/v=1/uδ/n, we obtain

1 | Q | Q H 3 ( x ) d x ( 1 | Q | Q | S ψ , δ ( ( b 1 ( b 1 ) Q ) ( b m ( b m ) Q ) g ) ( x ) | r v d x ) 1 / v C | Q | 1 / v ( Q | ( b 1 ( x ) ( b 1 ) Q ) ( b m ( x ) ( b m ) Q ) g ( x ) | r u d x ) 1 / u C | Q | 1 / v ( b 1 ( x ) ( b 1 ) Q ) ( b m ( x ) ( b m ) Q ) | f | r χ Q L v C b BMO | f | r B p δ .

For H 4 (x), we have

I 4 ( x ) [ R + n + 1 ( Q c | χ Γ ( x ) χ Γ ( x 0 ) | j = 1 m | b j ( z ) ( b j ) Q | | ψ t ( y z ) | | f ( z ) | r d z ) 2 d y d t t n + 1 ] 1 / 2 C k = 0 2 k + 1 Q 2 k Q | x 0 x | 1 / 2 | x 0 z | ( n + 1 / 2 2 δ ) | j = 1 m ( b j ( z ) ( b j ) Q ) | | f ( z ) | r d z C k = 1 2 k / 2 | 2 k + 1 Q | 1 + δ / n 2 k + 1 Q | j = 1 m ( b j ( z ) ( b j ) Q ) | | f ( z ) | r d z C k = 1 k m 2 k / 2 | 2 k Q | ( 1 / p δ / n ) b BMO | f | r χ 2 k Q L p C b BMO | f | r B p δ ,

so

1 | Q | Q | H 4 (x)|dxC b BMO | f | r B p δ .

This completes the proof of Theorem 2. □

References

  1. Coifman R, Rochberg R, Weiss G: Factorization theorems for Hardy spaces in several variables. Ann. Math. 1976, 103: 611–635. 10.2307/1970954

    Article  MathSciNet  MATH  Google Scholar 

  2. Garcia-Cuerva J, Rubio de Francia JL North-Holland Mathematics Studies 116. In Weighted Norm Inequalities and Related Topics. North-Holland, Amsterdam; 1985.

    Google Scholar 

  3. Liu LZ: The continuity of commutators on Triebel-Lizorkin spaces. Integral Equ. Oper. Theory 2004, 49: 65–76. 10.1007/s00020-002-1186-8

    Article  MATH  Google Scholar 

  4. Liu LZ, Wu BS: Weighted boundedness for commutator of Littewood-Paley integral on some Hardy spaces. Southeast Asian Bull. Math. 2004, 28: 643–650.

    MathSciNet  MATH  Google Scholar 

  5. Liu LZ:Weighted weak type ( H 1 , L 1 ) estimates for commutators of Littlewood-Paley operator. Indian J. Math. 2003, 45: 71–78.

    MathSciNet  MATH  Google Scholar 

  6. Pérez C, Trujillo-Gonzalez R: Sharp Weighted estimates for multilinear commutators. J. Lond. Math. Soc. 2002, 65: 672–692. 10.1112/S0024610702003174

    Article  MATH  Google Scholar 

  7. Stein EM: Harmonic Analysis: Real-Variable Methods, Orthogonality, and Oscillatory Integrals. Princeton University Press, Princeton; 1993.

    MATH  Google Scholar 

Download references

Author information

Authors and Affiliations

Authors

Corresponding author

Correspondence to Weiping Kuang.

Additional information

Competing interests

The author declares that they have no competing interests.

Rights and permissions

Open Access This article is distributed under the terms of the Creative Commons Attribution 2.0 International License (https://creativecommons.org/licenses/by/2.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

Reprints and permissions

About this article

Cite this article

Kuang, W. Endpoint estimates for vector-valued multilinear commutator of fractional area integral operator. J Inequal Appl 2013, 513 (2013). https://doi.org/10.1186/1029-242X-2013-513

Download citation

  • Received:

  • Accepted:

  • Published:

  • DOI: https://doi.org/10.1186/1029-242X-2013-513

Keywords