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Liouville theorems for a singular parabolic differential inequality with a gradient term

Abstract

In this paper, we study proofs of some new Liouville theorems for a strongly p-coercive quasi-linear parabolic type differential inequality with a gradient term and singular variable coefficients. The proofs are based on the test function method developed by Mitidieri and Pohozaev.

1 Introduction

We consider a singular quasi-linear parabolic differential inequality with a gradient term

u t Lua(x) u q b(x) | u | s ,xΩ,t>0,
(1.1)

and the initial condition is given by

u(x,0)= u 0 ,xΩ,
(1.2)

where q,s>0, Ω R N (N1) is a bounded domain with sufficiently smooth boundary or Ω= R N , the initial function u 0 L loc 1 (Ω) is nonnegative, and the coefficients a(x) and b(x) are positive and singular on the boundary Ω or at the origin 0.

Let A:Ω×R× R N R be a Carathéodory function and define an operator L as

Lu=div ( A ( x , u , u ) u ) ,

for any u W loc 1 , 1 (Ω×(0,)) such that A(x,u,u) L loc 1 (Ω×(0,)). The operator L is said to be strongly p-coercive (S-p-C), if there exist three constants c 1 , c 2 >0 and p>1 such that the inequality

c 1 | η | p 2 A(x,u,η) c 2 | η | p 2
(1.3)

holds for all (x,u,η)Ω×R× R N . For example, the Laplace operator is S-2-C and the p-Laplace operator is S-p-C.

Inequality (1.1) appears in many fields, such as fluid mechanics, biological species, and population dynamics, see [13]. From the perspective of fluid mechanics, (1.1) describes the non-Newtonian filtration phenomenon and the flow of gas in a porous medium, in which a(x) u q is called the source term and b(x) | u | s is called the gradient absorption term.

There have been many results on the nonexistence of nonnegative nontrivial global solutions for nonlinear parabolic type equations or inequalities (and systems), see [415] and references therein. In 1966, Fujita [4] studied the following Cauchy problem of the semilinear heat equation:

t uΔu= u p ,x R N ,t>0,

and he obtained the critical exponent q c =1+2/N on the existence versus nonexistence of nonnegative nontrivial global solution. From then on, there have been a number of extensions of Fujita’s results in many directions, and many scholars pay close attention to his results. The nonexistence of a global solution for nonlinear partial differential equations, which arises from the Liouville type theorem of harmonic function, is a nonlinear Liouville type theorem. Thus one can prove some properties of solutions in a bounded domain and this is a kind of essential reflection of blow-up or singularity theory as well, see [5] and references therein. In the whole space, Kartsatos [6] studied a Liouville type theorem on the solution for a quasi-linear parabolic equation without singular variable coefficient and gradient term. For a more general evolution and quasi-linear parabolic type inequality, see [7, 8] and references therein. By using the test function method, Mitidieri and Pohozaev [9, 10] studied the Liouville type theorems for elliptic and parabolic equations without gradient source term. Afterwards, by using the same method, Wei [11] obtained the nonexistence of the nonnegative nontrivial global weak solution for a semilinear parabolic inequality with a weight function a(x,t) ( | x | 2 + t ) γ , but without a gradient term. Note that the gradient term in the right-hand side of (1.1) will bring substantial difficulty to the research. In the whole space, Mitidieri and Pohozaev [12] put forward an important result for a differential inequality with a gradient nonlinearity; they considered the following quasi-linear elliptic inequality:

Δ p u u q | u | s ,x R N ,
(1.4)

and they proved that it has only constant solutions if 1<p<N, q>0, s0, q+s>p1, and q+ ( N 1 ) s N 2 < N ( p 1 ) N p . Later, Karisti and Filippucci did further research on general forms of (1.4) (cf. [13, 14]). Galakhov [15] discussed a strongly p-coercive elliptic, parabolic, and hyperbolic type differential inequality with a gradient nonlinearity of constant coefficient in bounded and unbounded domains. Moreover, they obtained a Liouville theorem by making use of the test function method. Recently, Li and Li [16, 17] extended their conclusions to the case of an elliptic type inequality with singular variable coefficients and obtained the nonexistence of solutions to that inequality and to the Harnack inequality. For singular parabolic problems in conical domains, refer to [1820] and the references therein.

Besides the works mentioned above, there are few studies on nonlinear Liouville theorems for a parabolic type differential inequality (1.1) with singular variable coefficients and a gradient term. The purpose of this paper is to investigate the influence of an S-p-C operator, the exponent of singular coefficients, and the gradient nonlinearity on the nonexistence of a nonnegative nontrivial global weak solution. The main difficulty lies in choosing a suitable test function according to different singularities of a(x), b(x), and inequality (1.1) with gradient nonlinearity. We will use the test function technique, developed by Mitidieri and Pohozaev [9, 10, 12], to show some Liouville theorems on the weak solution for problem (1.1)-(1.2) with bounded and unbounded domains. In particular, we recall that no use of comparison results and no conditions at infinity on the solution are required.

This paper is organized as follows: In Section 2, some preliminaries, such as some basic definitions and assumptions, and our main results are given. We prove the main results in Sections 3 and 4.

2 Preliminaries and main results

Since p>1 and inequality (1.1) is degenerate or singular, problem (1.1)-(1.2) has no classical solution in general, and so it is reasonable to consider other solutions. We state the two definitions of a weak solution and of a solution with a positive lower bound.

Definition 1 A nonnegative function u(x,t) is called a weak solution of problem (1.1)-(1.2) in S=Ω×(0,), if the following two conditions are satisfied:

  1. (i)

    A(x,u,u)u L loc 1 (S) and u W loc 1 , p (S) L loc q (S),

  2. (ii)

    for any nonnegative function φ C 0 1 (S), we have

    S a ( x ) u q φ d x d t Ω u 0 φ ( x , 0 ) d x S u t φ d x d t + S A ( x , u , u ) u φ d x d t + S b ( x ) | u | s φ d x d t .
    (2.1)

Definition 2 A nonnegative function u W loc 1 , p (S) L loc q (S) such that A(x,u,u)u L loc 1 (S) is said to be a solution with positive lower bound in S, if there exists c>0 such that u(x,t)c a.e. in S.

We consider two types of singularities.

Type 1: Both a(x) and b(x) are singular on the boundary Ω, i.e., there exist constants c 0 , d 0 >0 and α,βR such that

a(x) c 0 ρ ( x ) α ,b(x) d 0 ρ ( x ) β ,x Ω ε ,
(2.2)

where ρ(x)=dist(x,Ω) and Ω ε ={xΩ:ρ(x)ε} for sufficiently small ε>0.

Type 2: Both a(x) and b(x) are singular at the origin in the case that Ω= R N , i.e., there exist constants c 1 , d 1 >0 and α,βR such that

a(x) c 1 | x | α ,b(x) d 1 | x | β ,x R N {0}.
(2.3)

To establish a priori estimates of the solutions, we define some test functions which have the form of a separation of the variables, and those functions will be widely used in the sequel.

For the space variable and singular Type 1, we introduce a cut-off function ξ ε C 0 1 (Ω;[0,1]) that satisfies

0 ξ ε (x)1, ξ ε (x)=1in Ω Ω 2 ε , ξ ε (x)=0in  Ω ε ,

and

| ξ ε |c ε 1 ,xΩ,
(2.4)

for some constant c>0.

For the space variable and singular Type 2, we consider a cut-off function ξ R C 0 1 ( R N ;[0,1]) that satisfies

0 ξ R (x)1, ξ R (x)=1in  B R (0), ξ R (x)=0in  R N B 2 R (0),

and

| ξ R | c ˇ R 1 ,xΩ,
(2.5)

for some constant c ˇ >0.

Set

χ(x)= ξ λ ,
(2.6)

where λ>0 is a parameter to be chosen later according to the nature of problem (1.1)-(1.2).

For the time variable, assume that η(t) C ([0,)) and

0η(t)1,η(t)=1in [0,1],η(t)=0in [2,],C η (t)0.

Then, by appropriate combinations of the above functions, one can choose suitable test functions and obtain the following nonlinear Liouville theorems.

Theorem 1 Let p>1, q>max{1,p1, s p s }, and let s(0, p q q + 1 ). Suppose that A is S-p-C and a,b:Ω R + (or a,b: R N {0} R + ) are continuous functions that satisfy (2.2) (or (2.3)).

  1. (I)

    When both a(x) and b(x) are singular on Ω, if

    max{r,q1}<θ<q,α> θ p r θ r ,β< q ( p s ) s + α [ ( p s ) ( θ q ) + s ] θ q ,

then any nonnegative weak solution to problem (1.1)-(1.2) is trivial, i.e., u(x,t)=0 a.e. in S.

  1. (II)

    When both a(x) and b(x) are singular at 0, we consider the following two conditions: (i)

    max { r , q 1 , N r p } < θ < q , α < N ( 1 q ) θ + 1 q , β > N [ q ( p s ) s ] + α [ ( p s ) ( θ q ) + s ] θ q ;

    (ii)

    max { r , q 1 } < θ < min { q , N r p } , α < min { N ( 1 q ) θ + 1 q , θ p N r θ r } , β > N [ q ( p s ) s ] + α [ ( p s ) ( θ q ) + s ] θ q .

If one of the conditions (i) and (ii) holds, then any nonnegative weak solution to problem (1.1)-(1.2) is trivial, i.e., u(x,t)=0 a.e. in S, where θ is a parameter and r=q+1p.

Theorem 2 Suppose that the assumptions of Theorem  1 are satisfied. Then problem (1.1)-(1.2) has no solution with positive lower bound in S, if

α>porβ<α α s p ,

when both a(x) and b(x) are singular on Ω, or if

α<porβ>α α s p ,

when both a(x) and b(x) are singular at 0.

Remark 1 If inequality (1.1) is modified with

u t +Lua(x) u q b(x) | u | s ,xΩ,t>0,
(1.1a)

one can obtain the following results by a similar argument in the proof of Theorem 1.

Suppose that the assumptions of Theorem 1 are satisfied.

(I′) When both a(x) and b(x) are singular on Ω, if

θ>q,α> θ p r θ r ,β< q ( p s ) s + α [ ( p s ) ( θ q ) + s ] θ q ,

then any nonnegative weak solution to problem (1.1a)-(1.2) is trivial, i.e., u(x,t)=0 a.e. in S.

(II′) When both a(x) and b(x) are singular at 0, we consider the following two conditions: (i′)

θ > max { q , N r p } , α < N ( 1 q ) θ + 1 q , β > N [ q ( p s ) s ] + α [ ( p s ) ( θ q ) + s ] θ q ,

(ii′)

q < θ < N r p , α < min { N ( 1 q ) θ + 1 q , θ p N r θ r } , β > N [ q ( p s ) s ] + α [ ( p s ) ( θ q ) + s ] θ q .

If one of the conditions (i′) and (ii′) holds, then any nonnegative weak solution to problem (1.1a)-(1.2) is trivial, i.e., u(x,t)=0 a.e. in S, where θ is a parameter and r=q+1p.

Remark 2 Since Theorem 2 is independent of the parameter θ, one can also obtain the same results for problem (1.1a)-(1.2).

3 The proof of Theorem 1

Our proof mainly consists of three steps.

Step 1. For T>0, define Q Ω , T :=Ω×[0,2T] and let ψ(x,t)= η T (t)χ(x) be a cut-off function, where χ(x) is defined as (2.6) and η T (t)=η(t/T). Clearly, we get

C T η T ( t ) t 0.

For k>1, which will be determined later, and d=qθ>0, multiplying both sides of (1.1) with a test function Ψ= ψ k u d >0 and integrating the result over Q Ω , T , we have

Q Ω , T a ( x ) u q d ψ k d x d t Ω u 0 1 d χ k ( x ) d x Q Ω , T 1 1 d u 1 d ψ k t d x d t + Q Ω , T ( A ( x , u , u ) u ) u d ψ k d x d t + Q Ω , T ( A ( x , u , u ) u ) u d ψ k d x d t + Q Ω , T b ( x ) | u | s u d ψ k d x d t .

It follows from (1.3) that

Q Ω , T a ( x ) u θ ψ k d x d t + Ω u 0 1 d ( x ) χ k ( x ) d x Q Ω , T 1 d 1 u 1 d ψ k t d x d t c 1 d Q Ω , T u d 1 | u | p ψ k d x d t + c 2 k Q Ω , T u d ( | u | p 2 u ) ψ k 1 | ψ | d x d t + Q Ω , T b ( x ) | u | s u d ψ k d x d t .

By the definition of ψ, we get

Q Ω , T a ( x ) u θ ψ k d x d t + Ω u 0 1 d ( x ) χ k ( x ) d x + c 1 d Q Ω , T u d 1 | u | p ψ k d x d t C T Q Ω , T u 1 d ψ k 1 d x d t + c 2 k Q Ω , T u d | u | p 1 ψ k 1 | ψ | d x d t + Q Ω , T b ( x ) | u | s u d ψ k d x d t .
(3.1)

By applying Young’s inequality to the three terms in the right-hand side of (3.1), we obtain

C T Q Ω , T u 1 d ψ k 1 d x d t 1 4 Q Ω , T a ( x ) u θ ψ k d x d t + C T θ q 1 Q Ω , T a ( x ) q θ 1 q 1 ψ k θ q 1 d x d t ,
(3.2)
c 2 k Q Ω , T u d | u | p 1 ψ k 1 | ψ | d x d t c 1 d 4 Q Ω , T u d 1 | u | p ψ k d x d t + C Q Ω , T u θ r ψ k p | ψ | p d x d t ,
(3.3)

where r=q+1p,

Q Ω , T b ( x ) | u | s u d ψ k d x d t c 1 d 4 Q Ω , T u d 1 | u | p ψ k d x d t + C Q Ω , T b ( x ) p p s u ( p s ) ( θ q ) + s p s ψ k d x d t .
(3.4)

Since d>0, 0<1d=1q+θ<θ, 0<θr<θ, and ( p s ) ( θ q ) + s p s <s, we know that

max{r,q1}<θ<q,q>max { 1 , p 1 , s p s } ,s ( 0 , p q q + 1 ) .

Applying Young’s inequality to the two terms in the right-hand side of (3.3) and (3.4) yields

C Q Ω , T u θ r ψ k p | ψ | p d x d t 1 4 Q Ω , T a ( x ) u q d ψ k d x d t + C Q Ω , T a ( x ) r θ r ψ k r p θ r | ψ | θ p r d x d t ,
(3.5)
C Q Ω , T b ( x ) p p s u ( p s ) ( θ q ) + s p s ψ k d x d t 1 4 Q Ω , T a ( x ) u θ ψ k d x d t + C Q Ω , T a ( x ) ( p s ) ( θ q ) s q ( p s ) s b ( x ) θ p q ( p s ) s ψ k d x d t .
(3.6)

Let k be large enough such that k>max{ θ q 1 ,p, p θ r }. From inequalities (3.1)-(3.6), we deduce

1 4 Q Ω , T a ( x ) u θ ψ k d x d t + Ω u 0 1 d ( x ) χ k ( x ) d x + c 1 d 2 Q Ω , T u d 1 | u | p ψ k d x d t C T θ q 1 Q Ω , T a ( x ) q θ 1 q 1 ψ k θ q 1 d x d t + C Q Ω , T a ( x ) r θ r ψ k r p θ r | ψ | θ p r d x d t + C Q Ω , T a ( x ) ( p s ) ( θ q ) s q ( p s ) s b ( x ) θ p q ( p s ) s ψ k d x d t .

We then have

0 T Ω a ( x ) u θ χ k d x d t C T θ q 1 0 T Ω a ( x ) q θ 1 q 1 χ k θ q 1 d x d t + C 0 T Ω a ( x ) r θ r χ k r p θ r | χ | θ p r d x d t + C 0 T Ω a ( x ) ( p s ) ( θ q ) s q ( p s ) s b ( x ) θ p q ( p s ) s χ k d x d t .

It can be seen that | χ | θ p r = λ θ p r ξ θ p ( λ 1 ) r | ξ | θ p r , and we take λ>max{1, θ p k r }. We then obtain

0 T Ω a ( x ) u θ χ k d x d t C T θ q 1 0 T supp | ξ | a ( x ) q θ 1 q 1 ξ λ ( k θ q 1 ) d x d t + C λ θ p r 0 T supp | ξ | a ( x ) r θ r ξ λ ( k r p θ ) r | ξ | θ p r d x d t + C 0 T supp | ξ | a ( x ) ( p s ) ( θ q ) s q ( p s ) s b ( x ) θ p q ( p s ) s ξ λ k d x d t C T θ q 1 0 T supp | ξ | a ( x ) q θ 1 q 1 d x d t + C λ θ p r 0 T supp | ξ | a ( x ) r θ r | ξ | θ p r d x d t + C 0 T supp | ξ | a ( x ) ( p s ) ( θ q ) s q ( p s ) s b ( x ) θ p q ( p s ) s d x d t .
(3.7)

Step 2. When both a(x) and b(x) are singular on Ω, we take ξ= ξ ε in (3.7). Evidently, one has

supp|ξ|= Ω 2 ε Ω ε = { x Ω : ε ρ ( x ) 2 ε } .
(3.8)

By (2.2), we get

0 T Ω a ( x ) u θ ξ k λ d x d t C T θ q 1 0 T Ω 2 ε Ω 2 ε ρ ( x ) α ( q θ 1 ) q 1 d x d t + C λ θ p r 0 T Ω 2 ε Ω 2 ε ρ ( x ) α ( r θ ) r | ξ ε | θ p r d x d t + C 0 T Ω 2 ε Ω 2 ε ρ ( x ) α [ ( p s ) ( θ q ) + s ] β θ p q ( p s ) s d x d t .
(3.9)

By a standard change of variables and (2.4), we then obtain

0 T Ω Ω 2 ε a ( x ) u θ d x d t 0 T Ω a ( x ) u θ ξ k λ d x d t C T θ q 1 0 T Ω 2 ε Ω 2 ε ρ ( x ) α ( q θ 1 ) q 1 d x d t + C λ θ p r 0 T Ω 2 ε Ω 2 ε ρ ( x ) α ( r θ ) r | ξ ε | θ p r d x d t + C 0 T Ω 2 ε Ω 2 ε ρ ( x ) α [ ( p s ) ( θ q ) + s ] β θ p q ( p s ) s d x d t = C T θ q 1 0 T { x Ω : ε ρ ( x ) 2 ε } ρ ( x ) α ( q θ 1 ) q 1 d x d t + C λ θ p r 0 T { x Ω : ε ρ ( x ) 2 ε } ρ ( x ) α ( r θ ) r | ξ ε | θ p r d x d t + C 0 T { x Ω : ε ρ ( x ) 2 ε } ρ ( x ) α [ ( p s ) ( θ q ) + s ] β θ p q ( p s ) s d x d t C T θ q 1 ε α ( q θ 1 ) q 1 0 T Ω 2 ε Ω ε d x d t + C λ θ p r ε α ( r θ ) θ p r 0 T Ω 2 ε Ω ε d x d t + C ε α [ ( p s ) ( θ q ) + s ] β θ p q ( p s ) s 0 T Ω 2 ε Ω ε d x d t C T q θ 1 q 1 ε α θ ( q 1 ) ( α 1 ) q 1 + C T ε r ( 1 α ) + θ ( α p ) r + C T ε α [ ( p s ) ( θ q ) + s ] β θ p + q ( p s ) s q ( p s ) s = C T q θ 1 q 1 ε σ 1 + C T ε σ 2 + C T ε σ 3 ,
(3.10)

where

σ 1 = α θ ( q 1 ) ( α 1 ) q 1 , σ 2 = r ( 1 α ) + θ ( α p ) r , σ 3 = α [ ( p s ) ( θ q ) + s ] β θ p + q ( p s ) s q ( p s ) s .

By the conditions in (I) of Theorem 1, we have σ 1 >0, σ 2 >0, and σ 3 >0. Then, letting ε0 and combining with a random selection of T yield

S a(x) u θ dxdt=0,
(3.11)

and hence we get u(x,t)=0 a.e. in S.

Step 3. When both a(x) and b(x) are singular at {0}, take Ω= R N .

Choosing ξ= ξ R in (3.7), one has

supp|ξ|= B 2 R (0) B R (0)= { x Ω : R | x | 2 R } .
(3.12)

It follows from (2.3) that

0 T R N a ( x ) u θ χ k d x d t C T θ q 1 0 T B 2 R ( 0 ) B R ( 0 ) | x | α ( q θ 1 ) q 1 d x d t + C λ θ p r 0 T B 2 R ( 0 ) B R ( 0 ) | x | α ( r θ ) r | ξ R | θ p r d x d t + C 0 T B 2 R ( 0 ) B R ( 0 ) | x | α [ ( p s ) ( θ q ) + s ] β θ p q ( p s ) s .
(3.13)

Combining the above result with (2.5), we get

0 T B R ( 0 ) a ( x ) u θ d x d t 0 T R N a ( x ) u θ χ k d x d t C T θ q 1 0 T B 2 R ( 0 ) B R ( 0 ) | x | α ( q θ 1 ) q 1 d x d t + C λ θ p r 0 T B 2 R ( 0 ) B R ( 0 ) | x | α ( r θ ) r | ξ R | θ p r d x d t + C 0 T B 2 R ( 0 ) B R ( 0 ) | x | α [ ( p s ) ( θ q ) + s ] β θ p q ( p s ) s = C T θ q 1 0 T { x Ω : R | x | 2 R } | x | α ( q θ 1 ) q 1 d x d t + C λ θ p r 0 T { x Ω : R | x | 2 R } | x | α ( r θ ) r | ξ R | θ p r d x d t + C 0 T { x Ω : R | x | 2 R } | x | α [ ( p s ) ( θ q ) + s ] β θ p q ( p s ) s d x d t C T θ q 1 R α ( q θ 1 ) q 1 0 T B 2 R ( 0 ) B R ( 0 ) d x d t + C R α ( r θ ) θ p r 0 T B 2 R ( 0 ) B R ( 0 ) d x d t + R α [ ( p s ) ( θ q ) + s ] β θ p q ( p s ) s 0 T B 2 R ( 0 ) B R ( 0 ) d x d t C T q θ 1 q 1 R N α ( q θ 1 ) q 1 + C T R N α ( r θ ) + θ p r + C T R N α [ ( p s ) ( θ q ) + s ] + β θ p q ( p s ) s = C T θ q 1 R σ 4 + C T R σ 5 + C T R σ 6 ,
(3.14)

where

σ 4 = N α ( q θ 1 ) q 1 , σ 5 = N α ( r θ ) + θ p r , σ 6 = N + α [ ( p s ) ( θ q ) + s ] β θ p q ( p s ) s .

If one of the conditions (i) and (ii) in (II) of Theorem 1 holds, we have σ 4 <0, σ 5 <0, and σ 6 <0. Then, letting R and combining with a random selection of T, we finally arrive at

S a(x) u θ dxdt=0.
(3.15)

Therefore, we obtain u(x,t)=0 a.e. in S, and the proof is completed.

4 The proof of Theorem 2

In this proof, we use the method of contradiction. We take the same test function as in Section 3 and the proof is similar to that of Theorem 1. Suppose there exists u such that uc>0.

  1. (i)

    Assume that both a(x) and b(x) are singular on Ω. It follows from (2.2), (3.7), and (3.10) that

    0 T Ω 2 ε Ω ε ρ α (x) u θ χ k dxdtC T q θ 1 q 1 ε σ 1 +CT ε σ 2 +CT ε σ 3 .

By the definition of χ and the assumption uc>0, we have

C T q θ 1 q 1 ε σ 1 +CT ε σ 2 +CT ε σ 3 CT ε 1 α .

Then

max { T θ q 1 ε σ 1 , ε σ 2 , ε σ 3 } ε 1 α ,

i.e., one of following inequalities holds:

T θ q 1 ε 1 α σ 1 , ε σ 2 ε 1 α , ε σ 3 ε 1 α .
(4.1)

Since 0<ε<1, if α>p or β<α α s p , and T>1 is large enough and ε is sufficiently small, all inequalities in (4.1) do not hold, which is a contradiction.

  1. (ii)

    Assume that both a(x) and b(x) are singular at 0. By combining (2.3) and (3.7) with (3.14), we get the inequality

    0 T B R ( 0 ) | x | α u θ dxdtC T q 1 θ q 1 R σ 4 +CT R σ 5 +CT R σ 6 .

Combining this inequality with uc>0, we have

C T θ q 1 R σ 4 +CT R σ 5 +CT R σ 6 CT R N α ,

i.e., max{ T θ q 1 R σ 4 , R σ 5 , R σ 6 } R N α . Clearly, we have the inequalities

R σ 5 R N α , R σ 6 R N α .
(4.2)

If α<p or β>α α s p , the inequalities in (4.2) do not hold, which is a contradiction. The proof is completed.

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Acknowledgements

This work is supported by the Natural Science Foundation of Shandong Province of China (ZR2012AM018) and the Fundamental Research Funds for the Central Universities (No. 201362032). The authors would like to sincerely thank all the reviewers for their insightful and constructive comments.

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Fang, Z.B., Xu, L. Liouville theorems for a singular parabolic differential inequality with a gradient term. J Inequal Appl 2014, 62 (2014). https://doi.org/10.1186/1029-242X-2014-62

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